I have an array with mostly 6 lines:
01 ...
02 ...
03 ...
04 ...
05 ...
06 ...
01 ...
02 ...
etc.
Every so often the sixth line is missing:
01 ...
02 ...
03 ...
04 ...
05 ...
01 ...
I want to find the five line sets so I tried to Find %05%01 but I get no results.
How do I find start of lines over two consecutive lines?
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Find start of line over two consecutive lines
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Find start of line over two consecutive lines
by sduraybito » Fri Dec 28, 2012 11:36 am
- sduraybito
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Re: Find start of line over two consecutive lines
by Mofi » Sat Dec 29, 2012 9:08 am
The UltraEdit regular expression character % for beginning of a line can be used only once in a search string at beginning.
The right UltraEdit regular expression for a file with DOS line terminators for your use case would be %05*^p01
But there is a problem with this expression. It matches also
05 ...
06 ...
01
although it should match only
05 ...
01
UltraEdit regular expression character * should match any number of occurrences of any character except newline characters. And this works, but not if * is left of ^p in a search string. Then the expression * becomes greedy and matches also newline characters. I know about this bug in the UltraEdit regular expression engine very well.
However, there is a very simple workaround for this bug: instead of * the expression ?++ is used which means also zero or more occurrences of any character except newline characters and which does not have the unwanted greedy behavior.
So %05?++^p01 is the UltraEdit regular expression search string you need for this task.
Alternatively the UltraEdit regexp search strings %05[~^p]++^p01 or %05[~^r^n]++^p01 could be used too.
[~^p]++ respectively [~^r^n]++ means NOT a carriage return or line-feed character zero or more times which is equal the expression ?++.
The search string would be ^05.*\r\n01 or alternatively ^05[^\r\n]*\r\n01 with the Perl regular expression engine.
Either the search string ^05[^\r\n]*\r\n01 or the string ^05[^\p]*\p01 must be used with the legacy Unix regular expression engine.
The Unix regexp search strings ^05.*\r\n01 or ^05.*\p01 show the same greedy behavior as UltraEdit regexp search string %05*^p01.
The right UltraEdit regular expression for a file with DOS line terminators for your use case would be %05*^p01
But there is a problem with this expression. It matches also
05 ...
06 ...
01
although it should match only
05 ...
01
UltraEdit regular expression character * should match any number of occurrences of any character except newline characters. And this works, but not if * is left of ^p in a search string. Then the expression * becomes greedy and matches also newline characters. I know about this bug in the UltraEdit regular expression engine very well.
However, there is a very simple workaround for this bug: instead of * the expression ?++ is used which means also zero or more occurrences of any character except newline characters and which does not have the unwanted greedy behavior.
So %05?++^p01 is the UltraEdit regular expression search string you need for this task.
Alternatively the UltraEdit regexp search strings %05[~^p]++^p01 or %05[~^r^n]++^p01 could be used too.
[~^p]++ respectively [~^r^n]++ means NOT a carriage return or line-feed character zero or more times which is equal the expression ?++.
The search string would be ^05.*\r\n01 or alternatively ^05[^\r\n]*\r\n01 with the Perl regular expression engine.
Either the search string ^05[^\r\n]*\r\n01 or the string ^05[^\p]*\p01 must be used with the legacy Unix regular expression engine.
The Unix regexp search strings ^05.*\r\n01 or ^05.*\p01 show the same greedy behavior as UltraEdit regexp search string %05*^p01.
-
Mofi - Grand Master
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Re: Find start of line over two consecutive lines
by sduraybito » Wed Jan 02, 2013 7:58 pm
Bingo! The regular expression works great!
Thanks for your help!
Thanks for your help!
- sduraybito
- Newbie
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- Joined: Tue Apr 24, 2012 11:01 pm
3 posts
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