Replace the LAST found "\" in every line with "\\"

[c4p0ne]

There are multiple "\" characters on each line, what is the proper syntax to replace the LAST "\" character in every line with "\\"?

thanks.

[pietzcker]

Perl regex:

Search for \\([^\\]*)$
Replace with \\\\\1

[c4p0ne]

Nice thanks, but doesn't seem to be working, it's selecting the "\" and everything after it sort of like:

???? ???\25644d244vcv4d13e8b79eb65bb029c73\}:J\fake@fakeaddress.com

I need to isolate only that last "\" and replace it with "\\" (on every subsiquent line as well).

[Mofi]

If you would have tried the replace, you would have seen that the replace works. Yes, the search strings also selects everything after last \ till end of line, but the replace does not modify this part. The string after last \ is tagged by ([^\\]*) and re-used in the replace string with expression \1 which means everything found by the expression in the first (...) of the search string.

[pietzcker]

Thanks for your support, Mofi!

Of course, using lookahead, you could also search for

\\(?=[^\\]*$)

and replace all with

\\\\

Then you really only select the last \ on the line. This will even be quite a bit faster than my previous solution, I expect.

[c4p0ne]

Thanks for your time and patience in this simple matter. It is much appreciated!

[mingwu]

pietzcker's lookahead version is the best.

Cheers,

Ming Wu