Copy first 10 character of line to end of line

[RedShark]

I have a file were I need to copy the first ten character (a unique code) to the end of the line:

This is the original
QPH11002450A.help=Remarks

This should be
QPH11002450A.help=Remarks (QPH11002450A)

Each line has a different length, for example;
QPH11002450A.help=Remarks to the manager

Each line starts with 3 characters and is followed by 8 or 6 numbers and one character. Basicly I need the text before the "." copied to the end of the line.

How can I do this with reg. expressions / find and replace?

[palou]

Hi RedShark,

Try this (without the quote""):

Find: "%^([a-zA-Z_0-9 ]+^).^(*^)$"
Replace: "^1.^2 (^1)"
Check: Regular Expression

This should make the job (expecting there is no other chars
than letters, numbers, underscore or space before the "." and
at least one of them).

Regards,
Alain

[RedShark]

Hi Palou,

Thanks, it worked great! And your example showed me a littble bit more of the use of regular expressions in my code!